The compound which reacts with HBr in accordance with the markownikaff's rules is
(A) Ch2=Ch2 (B) Cis-but-z-ene (C) Tians-but-2-ene
(D) (Ch3) C=Ch2
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B part
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Explanation:
As option A & B are symmetrical so it will make same product and there is no use of markovnikov's rule.
But in case of C & D,
Alkenes are unsymmetrical so it will make different product when it reacts with HBr in presence of peroxide according to anti-markovnikov's rule.
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