Question

The compound which reacts with HBr in accordance with the markownikaff's rules is

(A) Ch2=Ch2 (B) Cis-but-z-ene (C) Tians-but-2-ene
(D) (Ch3) C=Ch2​

Answer 1

B part

hope this answer is correct and would help u ❤️

Answer 2

Explanation:

As option A & B are symmetrical so it will make same product and there is no use of markovnikov's rule.

But in case of C & D,

Alkenes are unsymmetrical so it will make different product when it reacts with HBr in presence of peroxide according to anti-markovnikov's rule.