Question

The compound with higher molecule mass is [Atomic mass of Ca-40u, C-12u, 0-16u,
H-lu, Cl-35.5u]
(A) CaCO3 (B) CaO
(C) Ca (OH)2 (D) CaCl2​

Answer 1

Answer:

CaCl2

40+35.5+35.5=111

CaOH) 2

40+16+16+1+1=74

CaO

40+16=56

CaCO3

40+12+16+16+16=100