Chemistry, asked by santhozh06, 5 months ago

The compound with higher molecule mass is [Atomic mass of Ca-40u, C-12u, 0-16u,
H-lu, Cl-35.5u]
(A) CaCO3 (B) CaO
(C) Ca (OH)2 (D) CaCl2

Answers

Answered by srivaths7521

0

Answer:

CaCl2

40+35.5+35.5=111

CaOH) 2

40+16+16+1+1=74

CaO

40+16=56

CaCO3

40+12+16+16+16=100

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