Chemistry, asked by same5694, 8 months ago

The compressibility factor for an ideal gas is
(a) 1.5 (b) 1.0 (c) 2.0 (d) [infinity]

Answers

Answered by Fatimakincsem
0

The compressibility factor i Z =  1

Option (B) is correct.

Explanation:

The ideal gas equation is:

PV = nRT

Where

  • P is the pressure
  • V is the volume
  • n is the number of moles
  • R is the gas constant. Its value is  8.314 4621 J K−1 mol−1
  • T is the absolute temperature

Therefore Z = 1

Here Z is the compressibility factor and the property of an ideal gas.

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Answered by rashich1219
0

The compressibility factor for an ideal gas is  1.0.

Step by step explanation:

The mathematical relationship of  ideal gas is as follows.

                                        PV = nRT

P  =  pressure of the gas

V  =  volume of the gas

n  =  Number of moles of gas

R = The gas constant

T = Absolute temperature of gas

For an ideal gas,Z = 1

Z is the compressibility factor and the property of an ideal gas.

Hence, correct option is "b".

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