English, asked by rjrinfra, 7 months ago

the compressibility factor for one mole of a van der Waals gas at 0degree celcius and 100atm pressure is found to be 0.5.assume that the volume of gas molecule is negligible. the value of van der Waals constant 'a' is​

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Answered by rajnandinithalkari25
1

Answer:

We know that, Compressibility factor, Z = PV/RT

We know that, Compressibility factor, Z = PV/RT0.5 = 100 *V/0.082 *273

We know that, Compressibility factor, Z = PV/RT0.5 = 100 *V/0.082 *273∴ V = 0.1117L

We know that, Compressibility factor, Z = PV/RT0.5 = 100 *V/0.082 *273∴ V = 0.1117LNOTE : Further when volume of a gas molecule is negligible, van der Waal’s equation becomes

We know that, Compressibility factor, Z = PV/RT0.5 = 100 *V/0.082 *273∴ V = 0.1117LNOTE : Further when volume of a gas molecule is negligible, van der Waal’s equation becomes(P + a/V2) (V - 0) = RT

We know that, Compressibility factor, Z = PV/RT0.5 = 100 *V/0.082 *273∴ V = 0.1117LNOTE : Further when volume of a gas molecule is negligible, van der Waal’s equation becomes(P + a/V2) (V - 0) = RTOr PV = RT – a/V or a = RTV – PV2

We know that, Compressibility factor, Z = PV/RT0.5 = 100 *V/0.082 *273∴ V = 0.1117LNOTE : Further when volume of a gas molecule is negligible, van der Waal’s equation becomes(P + a/V2) (V - 0) = RTOr PV = RT – a/V or a = RTV – PV2Substituting the values

We know that, Compressibility factor, Z = PV/RT0.5 = 100 *V/0.082 *273∴ V = 0.1117LNOTE : Further when volume of a gas molecule is negligible, van der Waal’s equation becomes(P + a/V2) (V - 0) = RTOr PV = RT – a/V or a = RTV – PV2Substituting the valuesA = (0.082 * 0.1119 *273) – (100 * 0.1119 * 0.1119)

We know that, Compressibility factor, Z = PV/RT0.5 = 100 *V/0.082 *273∴ V = 0.1117LNOTE : Further when volume of a gas molecule is negligible, van der Waal’s equation becomes(P + a/V2) (V - 0) = RTOr PV = RT – a/V or a = RTV – PV2Substituting the valuesA = (0.082 * 0.1119 *273) – (100 * 0.1119 * 0.1119)= 1.253 atm L2 mol-2

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