The compressibility of a liquid is 4 × 10–8 N–1 m2. If 2 litre of liquid is subjected to extra pressure of 2 × 106 N/m2, then the decrease in volume of the liquid will be
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Answered by
0
Explanation:
C
0.75ml
Given,
Compressibility, k=5×10
−10
m
2
N
−1
Volume is V=100mL
Change in pressure ΔP=15×10
6
−0=15×10
6
Pa
Compressibility k=
ΔP
−
V
ΔV
Decrease in volume,
−ΔV=kVΔP=5×10
−10
×100×15×10
6
−ΔV=0.75mL
Hence, change in volume is 0.75mL
Answered by
0
Answer:
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Explanation:
ΔV = 4 × 10–8 × 2 × 106 × 2 × 10–3
= 1.6 × 10–4 m3
= 160 cc
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