Question

The compressibility of a liquid is 4 × 10–8 N–1 m2. If 2 litre of liquid is subjected to extra pressure of 2 × 106 N/m2, then the decrease in volume of the liquid will be

Answer 1

Explanation:

C

0.75ml

Given,

Compressibility, k=5×10

−10

m

2

N

−1

Volume is V=100mL

Change in pressure ΔP=15×10

6

−0=15×10

6

Pa

Compressibility k=

ΔP

−

V

ΔV

Decrease in volume,

−ΔV=kVΔP=5×10

−10

×100×15×10

6

−ΔV=0.75mL

Hence, change in volume is 0.75mL

Answer 2

Answer:

Mark me as brainliest

Explanation:

ΔV = 4 × 10–8 × 2 × 106 × 2 × 10–3

= 1.6 × 10–4 m3

= 160 cc