Question

the comsumption of electricity in a city increases by 10% per year.in how many years from now ,will it exceed twice the present consumption ?​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

After 7.27 years ( approx )

Step-by-step explanation:

let P be the present consumption,

Since, rate of increasing per year, r = 10% = 0.1,

Thus, the consumption after t years,

$A=P(1+r)^t$

$=P(1+0.1)^t$

$=P(1.1)^t$

If A = 2P,

$2P=P(1.1)^t$

$2=(1.1)^t$

Taking ln both sides,

$\ln 2 = t \ln (1.1)$

$\implies t =\frac{\ln 2}{\ln (1.1)}\approx 7.27$

Hence, after 7.27 years it will exceed twice the present consumption.

#Learn more:

The value of a machine worth rupees 500000 is depreciating at the rate of 10% every year.In how many years will it's value be reduced to rupees 364500?​

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