Physics, asked by SheenaAnnCaimoy, 11 months ago

The concave mirror shown below has an object placed 20cm in front. An image is formed in 35cm in front of the mirror. What is the nature of the image? Calculate the magnification of the image and the focal length of the mirror

Answers

Answered by Dhruvbeniwal
2

F= 46.6

M=1.7

Real enlarged inverted

Attachments:
Answered by muscardinus
9

The formed image is real, inverted and enlarged.

magnification, m = 1.75

Focal length, f = -46.67 cm

Explanation:

It is given that,

Object distance, u = -20 cm

Image distance, v = +35 cm (in front of the mirror)

If f is the focal length of the mirror. It can be calculated using mirrors formula as :

\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}

\dfrac{1}{f}=\dfrac{1}{(-20)}+\dfrac{1}{(35)}

f = -46.67 cm

If m is the magnification of the mirror. So,

m=\dfrac{-v}{u}

m=\dfrac{-35}{-20}

m = 1.75

The formed image is real, inverted and enlarged.

Learn more,

Mirror formula

https://brainly.in/question/13067316

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