Question

the concentration of a solution having 0.24M is reduced to 0.12M in 10 hours and 006M in 20 hours what is the rate constant of the reaction
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Answer 1

The rate constant of the reaction  is $0.0693hours^{-1}$

Explanation:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

For a first order reaction half life is independent of initial concentration. $t_{\frac{1}{2}}=\frac{0.693}{k}$

Half-life of first order reaction is = 10 hours

To calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{\frac{1}{2}}}$

$k=\frac{0.693}{10}=0.0693hours^{-1}$

The rate constant of the reaction  is $0.0693hours^{-1}$

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Answer 2

Answer: 0.0693hrs^-1

Explanation:

As t 1/2 is independent of initial concentration, it is a first order reaction.

t1/2= 10 hrs

∴k = 0.693/10

​      =0.0693hrs^-1