Question

The concentration of a solution of Al(NO3)3 is 0.3 M. What is the concentration of (NO3)- ions in this solution?

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

Explanation:

equivalent of al(no3)3= equivalent of no3-

and if they are present in same solution then volumes are equal

so molarity*valency factor = molarity*valency factor

so molarity of no3- = 0.9