Question

The concentration of Ag* ions in a given saturated solution of AgCl at 25°C is 1.06 x 10-5
ion per litre. The solubility product of AgCl is:
(A) 0.353 × 10 -10
(B) 0.530 × 10 - 10
(C) 1.12 × 10 - 10
(D) 2.12 x 10-10​

Answer 1

Answer:

C

Explanation:

Agcl - - - > Ag* + Cl-

S. S

So the the solubility product of Agcl = solubility of products

So S of Ag = S of cl

Ksp = Square of S

Ksp=(1.06 ×10*-5)*2

Ksp=1.12 ×10*-10