the concentration of H2 S o4 in a bottle label concentrated sulphuric acid is 18 M the solution has density of 1.84 gram per centimetre cube What is the mole fraction and weight percentage of H2 S o4 in the solution
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let the mass of solution be x
mass of h2so4 = x*98/100 = 49x/50
now mole fraction= no. of moles of sulphuric acid/ no. of moles of solution
= x/100
mass of water = x= (49*x/50)= x/50
no. of moles of water= x/50/18 = x/900
mole fraction = x/100/(x/100)+(x/900)
= (x/100)*(900/9x+1)
=9x/9x+1
now it is your choice that what will be the mass of solution
if x =100 g then
then mole fraction = 0.1
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