Question

The concentration of hcn and nacn in a solution is 0.01 molar each

Answer 1

hey

Explanation:

Components of buffer solution of 0.1 M HCn... Components of buffer solution of 0.1 M HCn and 0.2 M Nacn. ...

Therefore , it is an acidic buffer in which HCN is a weak acid and NaCN is providing its conjugate base (CN-).

Answer 2

Initial 0.01 M 0M 0M

Final 0.0M 0.01M 0.01M

So at equilibrium, [H+] = XM

[CN-]Total = [CN-]Acid + [CN-]Salt

= XM + 0.01M = 1.01M

[HCN] = 0.01M XM = 0.01M

= -log[H+] = log 7.2 X 10-10