Chemistry, asked by 537joshua, 24 days ago

The concentration of hydrogen peroxide in a solution is determined by titrating a 10.0 mL sample of the solution with permanganate ion under acidic conditions, producing manganese(II) ion and oxygen gas. If it takes 13.5 mL of 0.109 M MnO4–solution to reach the equivalence point, what is the molarity of the hydrogen peroxide solution?

Answers

Answered by baliramshrivastav366

Number of moles of KMnO

Number of moles of KMnO 4

Number of moles of KMnO 4 =

Number of moles of KMnO 4 = 1000

Number of moles of KMnO 4 = 1000MV

Number of moles of KMnO 4 = 1000MV =

Number of moles of KMnO 4 = 1000MV = 1000

Number of moles of KMnO 4 = 1000MV = 10000.145×46.9

Number of moles of KMnO 4 = 1000MV = 10000.145×46.9 =6.8×10

Number of moles of KMnO 4 = 1000MV = 10000.145×46.9 =6.8×10 −3

Number of moles of KMnO 4 = 1000MV = 10000.145×46.9 =6.8×10 −3 Number of moles of H

Number of moles of KMnO 4 = 1000MV = 10000.145×46.9 =6.8×10 −3 Number of moles of H 2

Number of moles of KMnO 4 = 1000MV = 10000.145×46.9 =6.8×10 −3 Number of moles of H 2 O

Number of moles of KMnO 4 = 1000MV = 10000.145×46.9 =6.8×10 −3 Number of moles of H 2 O 2

Number of moles of KMnO 4 = 1000MV = 10000.145×46.9 =6.8×10 −3 Number of moles of H 2 O 2 =6.8×10

Number of moles of KMnO 4 = 1000MV = 10000.145×46.9 =6.8×10 −3 Number of moles of H 2 O 2 =6.8×10 −3

Number of moles of KMnO 4 = 1000MV = 10000.145×46.9 =6.8×10 −3 Number of moles of H 2 O 2 =6.8×10 −3 ×2.5=0.017

Number of moles of KMnO 4 = 1000MV = 10000.145×46.9 =6.8×10 −3 Number of moles of H 2 O 2 =6.8×10 −3 ×2.5=0.017Mass of H

Number of moles of KMnO 4 = 1000MV = 10000.145×46.9 =6.8×10 −3 Number of moles of H 2 O 2 =6.8×10 −3 ×2.5=0.017Mass of H 2

Number of moles of KMnO 4 = 1000MV = 10000.145×46.9 =6.8×10 −3 Number of moles of H 2 O 2 =6.8×10 −3 ×2.5=0.017Mass of H 2 O

Number of moles of KMnO 4 = 1000MV = 10000.145×46.9 =6.8×10 −3 Number of moles of H 2 O 2 =6.8×10 −3 ×2.5=0.017Mass of H 2 O 2

Number of moles of KMnO 4 = 1000MV = 10000.145×46.9 =6.8×10 −3 Number of moles of H 2 O 2 =6.8×10 −3 ×2.5=0.017Mass of H 2 O 2 =0.017×34=0.578

Number of moles of KMnO 4 = 1000MV = 10000.145×46.9 =6.8×10 −3 Number of moles of H 2 O 2 =6.8×10 −3 ×2.5=0.017Mass of H 2 O 2 =0.017×34=0.578Mass % of H

Number of moles of KMnO 4 = 1000MV = 10000.145×46.9 =6.8×10 −3 Number of moles of H 2 O 2 =6.8×10 −3 ×2.5=0.017Mass of H 2 O 2 =0.017×34=0.578Mass % of H 2

Number of moles of KMnO 4 = 1000MV = 10000.145×46.9 =6.8×10 −3 Number of moles of H 2 O 2 =6.8×10 −3 ×2.5=0.017Mass of H 2 O 2 =0.017×34=0.578Mass % of H 2 O

Number of moles of KMnO 4 = 1000MV = 10000.145×46.9 =6.8×10 −3 Number of moles of H 2 O 2 =6.8×10 −3 ×2.5=0.017Mass of H 2 O 2 =0.017×34=0.578Mass % of H 2 O 2

Number of moles of KMnO 4 = 1000MV = 10000.145×46.9 =6.8×10 −3 Number of moles of H 2 O 2 =6.8×10 −3 ×2.5=0.017Mass of H 2 O 2 =0.017×34=0.578Mass % of H 2 O 2 =

Number of moles of KMnO 4 = 1000MV = 10000.145×46.9 =6.8×10 −3 Number of moles of H 2 O 2 =6.8×10 −3 ×2.5=0.017Mass of H 2 O 2 =0.017×34=0.578Mass % of H 2 O 2 = 20

Number of moles of KMnO 4 = 1000MV = 10000.145×46.9 =6.8×10 −3 Number of moles of H 2 O 2 =6.8×10 −3 ×2.5=0.017Mass of H 2 O 2 =0.017×34=0.578Mass % of H 2 O 2 = 200.578

Number of moles of KMnO 4 = 1000MV = 10000.145×46.9 =6.8×10 −3 Number of moles of H 2 O 2 =6.8×10 −3 ×2.5=0.017Mass of H 2 O 2 =0.017×34=0.578Mass % of H 2 O 2 = 200.578 ×100=2.9.

Answered by adventureisland

The concentration of hydrogen peroxide, H2O2, in a solution is determined by titrating a 13.0 mL sample of the solution with permanganate ion, producing manganese(II) ion and oxygen gas.

Part A

Enter the balanced chemical equation for the redox reaction that occurs in acidic solution.

Part B

If it takes 16.6 mL of 0.127 M permanganate solution to reach the equivalence point, what is the molarity of the hydrogen peroxide solution?

Explanation:

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