The concentration of the hydrogen peroxide solution is 3.0% (w/w) in water. Calculate the mass of hydrogen peroxide in 1 mL of the solution.
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The molarity is obtained as moles of solute in 1 L (1000 mL) of solution. In your case, 1 L of solution contains 300 g of H2O2 (PM=34.01 g/mol). Therefore, the molarity is (300 g/34.01 g/mol) = 8.82 M.
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From the given question the correct answer is:
The molarity is obtained as moles of solute in 1 L (1000 mL) of solution. In your case, 1 L of solution contains 300 g of H2O2 (PM=34.01 g/mol). Therefore, the molarity is (300 g/34.01 g/mol) = 8.82 M.
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