Question

the concentric circle loops having radius in the ratio 1:2 and current in the ratio 4:3 then the ratio of magnetic field at the centre will be

Answer 1

1/2=4/2hdhxhssjjzsok

Answer 2

Answer:

The ratio of the magnetic field at the center will be 8:3.

Explanation:

Given that,

The concentric circle loops having radius in the ratio 1:2 and current in the ratio 4:3.

We know that,

The magnetic field at the center of the concentric circle,

$B = \dfrac{\mu_{0}I}{2r}$

Here, I = current

r= radius of the circle.

The magnetic field

$B\propto\dfrac{I}{r}$

The magnetic field for first circle

$B_{1}\propto\dfrac{I_{1}}{r}$.....(I)

The magnetic field for first circle

$B_{2}\propto\dfrac{I_{2}}{2r}$.....(II)

Now, The ratio of the magnetic field at the circle

$\dfrac{B_{1}}{B_{2}}=\dfrac{I_{1}\times2r}{I_{2}\times r}$

$\dfrac{B_{1}}{B_{2}}=\dfrac{4\times2}{3\times1}$

$\dfrac{B_{1}}{B_{2}}=\dfrac{8}{3}$

Hence, The ratio of the magnetic field at the center will be 8:3.