Math, asked by kmaccollenbaugh, 4 months ago

The concession stand at the high school football stadium sells hot dogs and hamburgers to raise money for the high school athletic programs.
Each hot dog sold earns the programs $0.50, and each hamburger sold earns $0.75. This week, the concession stand sold a combination of
230 hot dogs and hamburgers and earned $138.50 for the athletic programs. If x represents the number of hot dogs sold and y represents the
number of hamburgers sold, which system of equations represents this situation?
O A. 0.750 + 0.50y = 138.50
+ = 230
OB. 0.501 + 0.75y = 230
I + y = 138.50
O c. 0.751 + 0.50y = 230
1 + y = 138.50
OD.
0.50 +0.75y = 138.50
x + y = 230
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Answers

Answered by ake05814
5

Answer:

The answer would be:

0.50x+0.75y=138.50 and x+y=230

Step-by-step explanation:

The profits are from hotdog and hamburger sales, the total raised is $138.50, if we multiply 0.5 with the number of hotdogs sold (x) and if we multiply 0.75 with the number of hamburgers sold (y), we would get the total earned.

Since x is number of hotdogs and y is number of burgers, if we add them together, we get 230 which is the total of both sold

Answered by xirimbimbij
0

Answer:

Step-by-step explanation:

Let x be the number of hot dogs sold, and y be the number of hamburgers sold. Each hot dog sold earns $0.50, so the total earnings from hot dogs sold can be represented as 0.50x. Each hamburger sold earns $0.75, so the total earnings from hamburgers sold can be represented as 0.75y. The total number of hot dogs and hamburgers sold together is 230 , so we have the equation x + y = 230. The total earnings from both hot dogs and hamburgers sold is $138.50, so we have the equation 0.50x + 0.75y = 138.50.

Therefore, the system of equations that represents this situation is:

x + y = 230

0.50x + 0.75y = 138.50

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