The concutive integers are as such when they are taken in incresing order are multiplied by 2,3,and 4 respectively, they add up to 56 .find these numbers
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Let the three integers be x, x+1 and x+2
If they are being multiplied
2(x)+3(x+1)+4(x+2) = 56
2x + 3x + 3 +4x + 8 = 56
9x + 11 = 56
9x = 56 – 11
9x = 45
x = 45÷9
x = 5
So the consecutive integers are 5, 6 and 7
If they are being multiplied
2(x)+3(x+1)+4(x+2) = 56
2x + 3x + 3 +4x + 8 = 56
9x + 11 = 56
9x = 56 – 11
9x = 45
x = 45÷9
x = 5
So the consecutive integers are 5, 6 and 7
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