The condition for the differntial equatio
Mdx + Ndy = 0 be exact differential
equation
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(1) (a) Mdx + Ndy = 0 is exact if My = Nx (one mark). (b) If Mdx + Ndy = 0 is exact, u(x, y) = 0 is a solution if u = ∫ M(x, y)dx + k(y) where integral is with respect to x (treating y to be a constant) and k(y) is a function of y.
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