The condition if two circles of equal radii cut orthoganlly
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Two circles with equal radius pass through centre of each other as shown in figure. If radius = r, the area of the overlapping region would be:


Circle.jpg (14.68 KiB) Viewed 27767 times
A:
2π
r
2
−
3
√
2
2πr2−32
B:
2π
r
2
−
π
8
2πr2−π8
C:
r
2
(
4π
3
−
3
√
4
)
r2(4π3−34)
D:
r
2
(
π
3
−
2
√
)
r2(π3−2)
E:
r
2
(
2π
3
−
3
√
2
)
r2(2π3−32)


Circle.jpg (14.68 KiB) Viewed 27767 times
A:
2π
r
2
−
3
√
2
2πr2−32
B:
2π
r
2
−
π
8
2πr2−π8
C:
r
2
(
4π
3
−
3
√
4
)
r2(4π3−34)
D:
r
2
(
π
3
−
2
√
)
r2(π3−2)
E:
r
2
(
2π
3
−
3
√
2
)
r2(2π3−32)
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