the condition that the roots of ax ³+bx²+cx+d=0 may be in A.P is 2b³+27a²d=9abc
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Let the roots be p,q,r. The roots are in A.P.
So,
2q=p+r,
3q=p+q+r.
Using theory of equations,
p+q+r= -b/a .
So, q= −b/3a .
But, q is a root of the given equation. So
aq 3+bq 2 +cq+d=0,
a( -b/3a ) 3 +b( −b/3a ) 2+c( −b/3a)+d=0,
Rearranging, we get
2b*3 +27a*2d=9abc.
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