The condition that the roots of the equation ax²+bx+c=0 may differ by 5 is
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as we know that difference of two roots is
|a-b|=(√(b^2-4ac))/a
given a-b=5
5=(√(b^2-4ac))/a
squaring on both sides
25=(b^2-4ac)/a^2
25a^2=b^2-4ac
b^2-25a^2=4ac
|a-b|=(√(b^2-4ac))/a
given a-b=5
5=(√(b^2-4ac))/a
squaring on both sides
25=(b^2-4ac)/a^2
25a^2=b^2-4ac
b^2-25a^2=4ac
Answered by
0
Answer:
b^2 - 25a^2 = 4ac
Step-by-step explanation:
a-b = square root of b^2 - 4ac / a
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