Question

the conductivity of a saturated solution of Ag3Po4 is 9*10^-6 and its equivalent conductivity is 1.50*10^-4 the ksp of Ag3Po4 is​

Answer 1

Answer:

To find Ksp we have to use the formulae of Ksp = 27s^4 for Ag3PO4 which we know. Where s is the solubility of the solution.

Now we have to find the solubility s of the following solution by using the formulae of solubility = 1000*κ/C, here C is the equivalent conductivity and κ is the conductivity of the saturated solution.

Solubility = 1000 * 9*10^-6 * 10^4 / 1.50.

Solubility is 60 on solving.

So, Ksp will be 27 * 60^4.

Ksp = 3.4*10^8.