the conductivity of a saturated solution of Ag3Po4 is 9*10^-6 and its equivalent conductivity is 1.50*10^-4 the ksp of Ag3Po4 is
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To find Ksp we have to use the formulae of Ksp = 27s^4 for Ag3PO4 which we know. Where s is the solubility of the solution.
Now we have to find the solubility s of the following solution by using the formulae of solubility = 1000*κ/C, here C is the equivalent conductivity and κ is the conductivity of the saturated solution.
Solubility = 1000 * 9*10^-6 * 10^4 / 1.50.
Solubility is 60 on solving.
So, Ksp will be 27 * 60^4.
Ksp = 3.4*10^8.
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