Question

The conductivity of a saturated solution of BaSO4 is 3.06 ×10^-6 and then its equivalent conductance is 1.53. The ksp for baso4 will be?

Answer 1

Solubility product (Ksp)=(Ba2+)(SO4^2-)=C^2Molar conductivity(m)=Equivalent conductivity× equivalent factor of the electrolyte(i.e. 2 in this case) and C=Conductance/m.So,Ksp =((3.06×10^-6)/(1.53×2))^2=10^-12
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Answer 2

Explanation:

learn Ksp concept for every compounds