Question

The conductivity of an aqueous solution of NaCl in a cell is 92ohm^-1cm^-1. The resistance offered by this cell in 250ohm. The cell constant of the cell is

Answer 1

Check This Solution Please .. And Follow Main If Its Helps You

Answer 2

Given :

Conductivity (σ) = 92 ohm⁻¹cm⁻¹

Resistance (R) = 250 Ω

To Find :

Cell constant of the cell

Solution :

We know, Resistance (R) = $\frac{1}{Conductivity}$ × Cell constant

We are required to find the cell constant of the cell having resistance 250 Ω

∴   Resistance        =   $\frac{1}{92}$ × cell constant

⇒    250                 =   $\frac{1}{92}$ × Cell constant  

⇒  Cell constant    =  250 × 92

∴   Cell constant    = 23000 cm⁻¹

Hence, the cell constant of the given cell is found to be 23000 cm⁻¹.