Question

The conductivity of saturated solution of baso4 is 3,06 into 10 power -6 and its equivalent conductance is 1.53 the ksp for baso4 is

Answer 1

$\\ \red{ \bold{ \underline{ \bf{ANSWER }}}}$

$\\ \green{concepts}$

• molar conductance = n × equivalent conductance .
• n is n - factor
• or no of moles of electron loss or gai ed per mole of salt.
• at infinite dilution molar conductance is equal to molar conductance at infinite dilution.
• as saturated solution of sparingly soluble salt is extremely dilute. because these are usually form ppt but in excess of water they dissociate in small amount.
• examples are BaSo4, PbCl3, Agcl, agbr, Agi etc.
• now finally

$\\ \\ \land _m^\circ = \frac{1000k}{c} \\ \text{ \footnotesize{Where c is molarity and hence solubility \: (Infinite dilution)}} \\ \\ \:$

• solubility is maximum molarity of salt dissolved in solution.

$\\ \green{solution}$

• see attachment
• hope it helps
• not :- here wrong otions given