Question

the conjucate of 2-i/(1-2i)^2 is​

Answer 1

Step-by-step explanation:

2-i/1+4i^2-4i

2-i/1+4(-1)-4i

2-i/1-4-4i

2-i/-3-4i

conjugate of the above eq is

2+i/-3+4i

this will be answer

but if we can more simplify

we always remove i from the denominator so we intiallized the equation.we will multiply the equation by changing the denominator sign

2+i/-3+4i×-3-4i/-3-4i

2+i×(-3-4i)/(-3)^2-(4i)^2

-6-8i-3i-4i^2/9-16i^2

-6-10i-4(-1)/9-16(-1) i^2=-1

-6-10i+4/9+16

-2-10i/25

-2/25-10i/25

-2/25-2i/5