Question

the conjugate complex of (3+4i) ( 2-3i) is​

Answer 1

Step-by-step explanation:

(3 + 4i) (2 - 3i)

=> 6 + 8i - 9 i - 12 i^2

=> 6 - i - 12 (-1)   ...[i^2 = -1]

=> 6 - i + 12

=> 18 - i

                        Solved By

                 Aaditya Singh

Answer 2

Answer:

The conjugate complex of $(3+4i) ( 2-3i)$ is $18+i$.

Step-by-step explanation:

According to the question , we are given a complex number in the form of multiplication of two complex numbers and we need to find out the complex conjugate number of this complex number which is given in our question.

So firstly we need to solve the equation and find out the complex number which complex cponjugate we need to find out. If we find out the number then easily we can find out the complex conjugate number.

$(3+4i) ( 2-3i)\\\\= 6 -9i +8i+12\\\\=18 -i$

So the conjugate complex of $(3+4i) ( 2-3i)$ is $18+i$.

#SPJ3