the conjugate of 2-root 3 is
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2 + √3 is the answer.....
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Answer. If a = √3 and b= 1 ,then denominator is ( a-b) , if we multiply ( a+b) or √3+1 , it will a2-b2 and √3 will be squared off. = 2(\sqrt{3}+1) . In above example √3+1 is used as rationalizing factor which is a conjugate to √3-1 .
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