Math, asked by mallinettem, 9 months ago

the conjugate of 3+root 5 is a +b root 5 and a,b roots of the QE x²-2x-k =0 then k is

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Answered by itzcrazyboy47

Answer:

Complex roots always exist in conjugate pairs. ... If x=3 is one root of the quadratic equation xsquare - 2kx - 6 = 0, then what is the value of k ...

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Answered by tennetiraj86

Answer:

answer for the given problem is given

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the conjugate of 3+root 5 is a +b root 5 and a,b roots of the QE x²-2x-k =0 then k is​

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the conjugate of 3+root 5 is a +b root 5 and a,b roots of the QE x²-2x-k =0 then k is