Question

the conjugate of 7-2√3
(a)7-2√3
(b)7+2√3
(c)5-2√3
(d)5+2√3

Answer 1

Given :  Irrational number  7 - 2√3

To Find: Conjugate

(a)7-2√3

(b)7+2√3

(c)5-2√3

(d)5+2√3

Solution:

Conjugate pairs of binomials are used to rationalize denominators containing radical expressions.

if a  , b , c  and d are ration number then

conjugate of  a√b  + c√d   is   a√b - c√d

7 - 2√3

Comparing with

a√b  + c√d

a = 7  ,  b = 1

c = -2   , d = 3

Conjugate is

a√b - c√d

7 - (-2) √3

= 7 + 2√3

Hence , conjugate of 7-2√3  is 7 + 2√3

option b) is correct

Learn More:

Conjugate of the surd root 3 - root 5 is - Brainly.in

brainly.in/question/8946703

The conjugate surd of 2021-2022 is​ - Brainly.in

https://brainly.in/question/43496422

Answer 2

Answer:

Option B is the correct answer.