Math, asked by tanmaynandwana7921, 9 months ago

The conjugate of a complex number is 1/(i-1). Then the complex number is

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Answered by deva4583
4

Answer:

answer is 1-i/2 is conjugate

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Answered by BrainlySmile
1

Answer- The above question is from the chapter 'Complex Numbers'.

Given question: The conjugate of a complex number is 1/(i-1). Then the complex number is _____ .

Solution: Let z be a complex number.

\bar{z} is its conjugate.

\bar{z} = \dfrac{1}{i \: - \: 1}\\\\\bar{z} = \dfrac{1}{i \: - \: 1} \times \dfrac{i \: + \: 1}{i \: + \: 1}\\\\\bar{z} = \dfrac{i \: + \: 1}{i^{2} \: - \: 1^{2}}\\\\\bar{z} = \dfrac{i \: + \: 1}{-1 - 1}\\\\\bar{z} = \dfrac{i \: + \: 1}{-2}\\\\\bar{z} = \dfrac{-(i \: + \: 1)}{2}\\

\bar{z} = \dfrac{-1 - i}{2}

z and \bar{z}  are conjugates of each other.

So, if

\bar{z} = \dfrac{-1 - i}{2}

then,

z =  \dfrac{-1 + i}{2}

So, the required complex number is z =  \dfrac{-1 + i}{2}

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