Question

The conjugate surd of root 2 minus 1​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

if simplification of the complex surd 63√−1 is to be done, denominator 3–√−1 is to be converted to a rational number. If a = 3–√ and b = 1, then denominator is (a-b), if we multiply (a + b) or 3–√+1, it will a2−b2 and 3–√ will be squared off.

63√−1

= 6(3√+1)(3√−1)(3√+1)

= 6(3√+1)3−1

= 6(3√+1)2

= 2(\sqrt{3} + 1).

In the above example 3–√+1 is used as rationalizing factor which is a conjugate to 3–√−1.