Question

the conpound interest on rs 6250 at 8% per annum for 1 year compounded half yearly​

Answer 1

$\huge\bold{Question:-}$

The compound interest on rs 6250 at 8% per annum for 1 year compounded half yearly.

$\huge\bold{Given:-}$

• Principal = Rs. 6250

• Rate = 8%

• Time taken = 1yrs.

$\boxed {Note}$ :- Compound Interest is taken yearly.

$\huge\bold{To\:find:-}$

• Compound interest?

$\huge\bold{Formula\:used:-}$

• $a = p(1 + \dfrac{r}{100})t$

• $amount - principal = c.i.$

$\bold{Step-by-step-explanation:-}$

$= 6250(1 + \dfrac{8}{100})1$

$= 6250( \dfrac{100 + 8}{100})1$

$= 6250 \times \dfrac{108}{100} \times 1$

$= 6750$

Thus, Amount = Rs 6750

_________________

Compound interest = Amount - Principal

C.I. = 6750 - 6250

= Rs 500

Answer 2

$\begin{lgathered}\begin{lgathered}\begin{lgathered}\tt {\pink{Given}}\begin{cases} \sf{\green{Principal (P) = Rs.6,250}}\\ \sf{\blue{Rate\: of\: interest = 8}}\\ \sf{\orange{Time (t) = 1 year}}\end{cases}\end{lgathered} \:\end{lgathered}\end{lgathered}$

⠀

$\large{\underline{\tt{To\: find}}}$

• The Compound Interest.

⠀

$\large{\underline{\tt{Solution}}}$

⠀

We know that

$\large{\underline{\boxed{\tt{Amount = P (1 + \dfrac{r}{100})t}}}}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {Amount = 6250 × (1 + \dfrac{8}{100}) × 1 }$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {Amount = 6250 × (\dfrac{100 + 8}{100}) × 1}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {Amount = \not{6250} × \dfrac{108}{\not{100}}}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {Amount = 125 × \dfrac{108}{2}}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {Amount = 125 × 54}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {Amount = Rs.6,750 }$

⠀

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Now,

$\large{\underline{\boxed{\tt{C.I = Amount - Principal}}}}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {C.I = 6,750 - 6,250 }$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {C.I = Rs.500}$