Question

The consecutive class marks of a distribution are 37,42,47, 52 and 57. determine the class size and the class limits of the last class mark

Answer 1

Answer:

class mark=5.

class limits=54.5-59.5

Step-by-step explanation:

Given: class marks= 37,42,47,52 and 57

class size= difference between two consecutive class marks=42-37=5.

let lower limit of the last class interval='a'.

then, upper limit = a+5.

class mark = average of upper and lower limits of the class interval.

57=(a+a+5)/2,

2a+5=57×2=114,

2a=114-5=109,

a=109/2=54.5.

therefore lower limit = a = 54.5,

and upper limit = a+6 = 54.5+5 = 59.5.

Answer 2

Step-by-step explanation:

In the given data class marks are uniformly spaced. So, the Class size is the difference between any two consecutive class marks.

∴ Class size = 42 – 37 = 5

we know that if a is the class marks of class interval and h is its class size then the lower and upper limits of the class intervals areandrespectively.

∴ lower limit of first class interval =

and upper limit of first class interval =

So the first class interval is 34.5 – 39.5 similarly we obtain the other class limits