The consecutive digits of a three-digit number form a G.P. If we subtract 792 from this number, we get a number
consisting of the same digits written in the reverse order and if we increase the second digit of the required number
by 2, the digits of resulting number form an A.P. The number is:
(A) 139
(B) 193
(C) 931
(D) None of these
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Answer:
the answer is 931
because if we subtract 792 from 931 we gets 139
if second digit increases by 2 it becomes 5 and 1,5,9 are in AP.
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