Question

the consecutive integers are such that when they are taken in increasing order multiplied by 2,3,4 respectively they add up to 74 numbers find these numbers ​

Answer 1

Step-by-step explanation:

Answer 2

GivEn

• If three consecutive integers are taken in ascending order and multiplied by 2,3,4 they total add up to 74.

To finD:

• Those three numbers

Solution:

Let suppose that first number is x.

Now,

Given that next number will be in ascending order so,

Other two consecutive number will be x+1 and x+2

Our three numbers that we have supposed are :

• x
• x+1
• x+2

Now,

According the given condition :

2(x) +3(x+1)+4(x+2) = 74

=> 2x + 3x + 3 + 4x +8 = 74

=> 2x + 3x + 4x + 3 +8 = 74

=> 9x + 11 = 74

=> 9x = 74 - 11

=> 9x = 63

=> x = 63/9

=> x = 7

Therefore,

We found that first number (x) = 7.

So, another two numbers are :

• x + 1 = 7 + 1 =>8
• x + 2 = 7 + 2 => 9

Our answer :

Three consecutive number which are multiplied in ascending order given add up to 74 are : 7 ,8 and 9.

xx_____________________xx

Verification :

Let us see that is our answer correct?

To see it verify our answer, we will have to put the values of variables .

Putting value of variables on the place of variables :

2(x) +3(x+1)+4(x+2) = 74

=> 2(7) +3(7+1)+4(7+2) = 74

=> 14 + 24 + 36 = 74

=> 38 + 36 = 74

=> 74 = 74

LHS = RHS

Verified ✅