The consecutive multiples of 5 whose sum is 105 are
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Answered by
9
30+35+40= 105
30= 5•6
35= 5•7
40= 5•8
Answered by
17
let two consecutive number be 5x and 5(x+1)
then
5x+5(x+1)=105
10x=105-5
x=10
then
1st= 5×10= 50
2nd = 5(10+1)=55
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