The consecutive multiples of the number nine are 9,18,27,36,45,54,63,72,81,90,99,108,117,........The sum of the digits in these multiples are respectively 9,9,9,9,9,9,9,9,9,9,9,18,9...Find the least number which when multiplied by 9 gives a number the sum of whose digits is 27.
Answers
Given : The consecutive multiples of the number nine are 9,18,27,36,45,54,63,72,81,90,99,108,117,........The sum of the digits in these multiples are respectively 9,9,9,9,9,9,9,9,9,9,9,18,9...
To Find : least number which when multiplied by 9 gives a number the sum of whose digits is 27.
Solution:
Least number to have sum of digits as 27
can be 999
(∵ max digit is 9 hence 2 digit number maximum possible sum = 9 + 9 = 18
3 digit maximum possible sum 9 + 9 + 9 = 27 )
Divide the number by 9 to get the least number which when multiplied by 9 gives a number the sum of whose digits is 27.
999/9 = 111
111 is the least number which when multiplied by 9 gives a number the sum of whose digits is 27.
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Answer:
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