Question

the constant power is supplied to amotion along a straight line the distance described in time t is proportional to​

Answer 1

t³/²

Solution:—

$\to \sf \: we \: know \: that$

$\sf{power = } \frac{w}{t} = \frac{f \times d}{t} = f \times w$

So, P = F × V

$F = m \bold{LT} {}^{ - 2}$

$V = LT {}^{ - 1}$

$= [ mLT {}^{ - 2} ][ LT {}^{ - 1} ]$

$= mLT {}^{ - 3} = \sf constant$

$\frac{L²}{T³} = \sf constant$

L²aT³

LaT³/²

LaT³/² L is distance.

Hence, t³/² is Answer.

Answer 2

Answer:

t³/²

Solution:—

\to \sf \: we \: know \: that→weknowthat

\sf{power = } \frac{w}{t} = \frac{f \times d}{t} = f \times wpower=

t

w

=

t

f×d

=f×w

So, P = F × V

F = m \bold{LT} {}^{ - 2}F=mLT

−2

V = LT {}^{ - 1}V=LT

−1

= [ mLT {}^{ - 2} ][ LT {}^{ - 1} ]=[mLT

−2

][LT

−1

]

= mLT {}^{ - 3} = \sf constant=mLT

−3

=constant

\frac{L²}{T³} = \sf constant

T³

L²

=constant

L²aT³

LaT³/²

LaT³/² L is distance.

Hence, t³/² is Answer