Question

The constant term in the quadratic equation 3.r2-3(2r-4)=0, after reducing it to
the standard form ar+brte=0 is​

Answer 1

equation

Answer:

Let the actual quadratic equation be x

2

+bx+c=0

First student makes a mistake in constant. Let's say he took the constant as d

Hence the quadratic equation for the first student becomes x

2

+bx+d=0

The roots for this equation are 8 and 2

Sum of roots =−b=10

⇒b=−10

Product of the roots =16=d

⇒d=16

The second student makes a mistake in the coefficient of first degree term. Let's say he considered it to be e instead of b

The equation becomes x

2

+ex+c=0 with roots −9,−1

Sum of the roots =−10=−e

⇒e=10

Product of the roots =9=c

⇒c=9

Hence the actual quadratic equation becomes x

2

−10x+9=0