Question

The constant term in the quadratic equation 3x2

-3(2x-4)=0, after reducing it to

the standard form ax2

+bx+c=0 is

A. 3 B. 4

C. -12 D. 12​

Answer 1

Answer:

B. 4

Step-by-step explanation:

3x2 -3(2x-4)=0

=> 3x2 -6x+12=0

=>x2 -2x + 4 = 0

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Answer 2

Answer:

The correct answer is option B,D

Step-by-step explanation:

Given, equation : $3x^2 - 3(2x -4) =0$

To find: the constant term of the equation

Solution:

⇒$3x^2 - 6x + 12 =0$      [This is the standard form]

∴ The constant term is 12.

$3(x^2 - 2x + 4) =0\\x^2 - 2x + 4 =0$

The constant term is 4

Hence the correct answer is option B, D