Question

the constant term in the quadratic equation 3xsquare-3(2x-4)=0 after reducing it to the standard form ax square+b+c=0​

Answer 1

Answer:

12

Step-by-step explanation:

3x^2-3(2x-4)

= 3x^2-6x+12

Here we can clearly see that constant term is 12.

Answer 2

Correction:

The standard form is $a(x)^2 + bx + c = 0$ not $a(x)^2 + b + c = 0$

Answer:

-12

Step-by-step explanation:

Given equation,

$3(x)^2-3(2x-4) = 0$

Equating the equation, we get,

$3(x)^2 - {(3)(2x)} - (3)(4)= 0$

⇒ $3(x)^2 - {(6x)} - 12= 0$

Now as the equation is in the standard form we have,

a = 3,

b = -6,

c (Constant Term) = -12