Question

the construction of a traingle ABC in which AB=5.4 CM and angle q =60 degree is not possible when PQ+QR is ​

Answer 1

Answer:

Steps of construction:

Draw the base QR=6 cm. ...

Cut the line segment QS equal to PR-PQ=2 cm , from the ray QX extended on opposite side of base QR.

Join SR and draw its perpendicular bisector ray AB which intersect SR at M.

Let P be the intersection point of SX and perpendicular bisector AB.