the construction of a traingle ABC in which AB=5.4 CM and angle q =60 degree is not possible when PQ+QR is
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Steps of construction:
Draw the base QR=6 cm. ...
Cut the line segment QS equal to PR-PQ=2 cm , from the ray QX extended on opposite side of base QR.
Join SR and draw its perpendicular bisector ray AB which intersect SR at M.
Let P be the intersection point of SX and perpendicular bisector AB.
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