The construction of a triangle ABC,given that bc=10 cM, angle c -60 degree is possible when sum of ab and ac
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Class 9
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>>Construction of Triangles
>>To construct a ABC in which BC = 10 cm
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To construct a △ABC in which BC = 10 cm and B= 60oand AB + AC =14 cm, then the length of BD used for Construction:
A]. Draw the base BC and at the point, B makes an angle, say XBC equal to the given angle.
B]. Cut a line segment BD equal to AB+ACfrom the ray BX.
C]. Join DC and make an angle DCY equal to BDC.
D]. Let CY intersect BX at A
E]. ABC is the required triangle.
F]. In triangle ΔACD, ∠ACD=∠ADC.
G]. So, AB=BD–AD=BD–AC
H]. AB+AC=BD
From this we get, BD=14cm.
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