Question

the construction of a triangle ABC which AB =4cm and angle A=60 degree is not possible when difference of BC- AC is equal to​

Answer 1

Given: In Δ$ABC$, $AB=4cm$, and ∠$A=60^{o}$.

To find: the difference between BC and AC for constructing a triangle.

Step-by-step explanation:

Step 1 of 2

When we construct a triangle, the sum of two sides is always greater than the third side.

And the sum of all the angles in the triangle is equal to $180^{o}$.

Step 2 of 2

Using the statement stated in step 1:

$AC+AB>BC\\AB>BC-AC\\4>BC-AC$

THE CONSTRUCTION OF THE TRIANGLE IS IMPOSSIBLE IF THE DIFFERENCE $BC-AC$ IS GREATER THAN $4cm$.