Computer Science, asked by viratbabu9517, 4 months ago

The content of AC in the basic computer is hexadecimal A937 and the initial value of E is 1. Determine the contents of AC, E, PC, AR, and IR in hexadecimal after the execution of CLA instruction. Repeat 11 more times, starting from each one of the registerreference instructions. The initial value of PC is hexadecimal 021.

Answers

Answered by khushisathish100
11

Answer:

Ganesh. This festival is followed by another, Bhitauli which is celebrated in the month of Chaitra

Explanation:

Answered by AncyA
1

Answer:

The contents of (AC) = 0h,    E=1,   (PC)= 022h,   (AR) = 800h,    (IR) = 7800h

Explanation:

Solution:

The contents of AC, E, PC, AR and IR in hexadecimal after the execution of CLA instruction was given below,

Execute CLA ( Instruction code 7800h )

Fetch:

AR  <-  PC                                        ; =>  ( AR )  =  ( PC )  =  021h

IR   <-  M[AR]   , PC   <-  PC  +  1      ;  ( IR ) = 7800h,     ( PC )  =  022h    

Decode:

D0 , . . . , D7   <-  decode  IR ( 12 - 14 )

AR  <-  IR ( 0-11 )  , I  <-  IR ( 15 )  ;  => ( AR ) = 800h  (12 address bits)

Execute:

AC  <-  0                                             ;  ( AC )  =  0

Summary:

(AC)  =  0h,   ( AR )  =  800h,   ( PC )  =  022h,   ( IR )  =  7800h,   EC =  1

#SPJ3

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