Math, asked by realiblamevishi, 6 months ago

The contents of a certain box consist of 14 apples and 23 oranges. How many oranges must be removed from the box
so that 70% of the pieces or fruit in the box will be apples?
(a) 12
(b) 6
(c) 17
(d) 36​

Answers

Answered by ꜱᴄʜᴏʟᴀʀᴛʀᴇᴇ
4

Answer:

Let x be no of oranges to be removed

Total fruits are 14+23-x=37-x

70% is 0.7(37-x)=14

37-x=14/0.7=20

x=37–20=17

So the answer is (c) 17.

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Answered by nagaramkrideyp9a6rk
0

Answer:

C) 17

Step-by-step explanation:

Given

70% should be apple's

therefore 14 apples = 70%

x fruits = 100%

x = (14×100)/70

therefore x= 20

I.e total fruits is 20

but 14 are apples therefore there should be 6 oranges in total

therefore remove 17 oranges from the 23 oranges

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