Question

The contents of two cans containing alcohol and water in the ratio 1:2 and 2:3 respectively are mixed in the ratio of 3:5.what is the ratio of alcohol and water in the resultant solution

Answer 1

Answer:

The given numerical is quite easy but tricky example of ratio and proportion.

Consider first vessel,

The ratio of water to alcohol is 1 : 2

Now, 6 L solution is taken from first vessel.

Let, quantity of water be x. So, quantity of alcohol will be 2x.

So, x + 2x = 6

So, x = 2 L and 2x = 4L

Hence, 2 Liters of water and 4 liters of alcohol is taken out from first vessel.

Similarly, now consider 2nd vessel.

The ratio of water to alcohol is 3:4

35 Liters of solution is taken out.

Let, quantity of water taken out = 3x

So, quantity of alcohol taken out = 4x

Now, 3x + 4x = 35

So, x= 5

Hence, quantity of water taken out = 3x = 15 Liters

and quantity of Alcohol taken out = 4x = 20 Liters

Now, Solution is made by mixing 6L of solution from first vessel and 35L of solution from second vessel.

So, Total quantity of water in resultant solution = 15 L + 2 L = 17 L

and Total quantity of alcohol in resultant solution = 20L + 4L = 24 L

Hence, Ratio of Alcohol to Water in resultant solution = 24 : 17