the controls of a triangle divides
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the each median has 2:1
adiRana1:
well done
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In-center divides the angle bisectors in some definite ratio. Let ABC be a triangle AB=b, BC=a , AC=c & let bisector of angle A = AF touching BC at F . Then AF is divided in the ratio (b+c):a. Proceeding in this manner for other sides you will come to your answer . The answer will be 11:4.
Thank you
And I hope this will help you. .
Thank you
And I hope this will help you. .
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