The conversion A + Bfollows second
order kinetics. Doubling, the
concentration of A will increase the rate
of formation of 'B’by a factor of
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For the second order reaction,
Rate=k×[A]
2
if the concentration of A is doubled, then A becomes 2A in the rate reaction, which implies,
Rate=k×[2A]
2
⇒k×4×[A]
2
⇒4×k×[A]
2
∴ the rate of the formation of B increases by a factor of 4
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