Math, asked by saijasagi, 8 months ago

The conversion A + Bfollows second
order kinetics. Doubling, the
concentration of A will increase the rate
of formation of 'B’by a factor of
CA​

Answers

Answered by gurdialsingh556600
0

ANSWER

For the second order reaction,

Rate=k×[A]

2

if the concentration of A is doubled, then A becomes 2A in the rate reaction, which implies,

Rate=k×[2A]

2

⇒k×4×[A]

2

⇒4×k×[A]

2

∴ the rate of the formation of B increases by a factor of 4

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